Question 29

Given the standard electrode potentials,

K+/K = -2.93V, Ag+/Ag = 0.80V,

Hg2+/ Hg = 0.79V

Mg2+/ Mg = -2.37V. Cr3+/ Cr = -0.74V

Arrange these metals in their increasing order of reducing power.

Answer

The lesser the electrode potential, the stronger is the reducing agent. Therefore, the increasing order of the reducing power of the given metals is Ag < Hg < Cr < Mg < K.

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