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Question 7

In a process, 701 J of heat is absorbed by a system and 394 J ofwork is done by the system. What is the change in internal energy for the process?

Answer

According to the first law of thermodynamics,

ΔU= q + W    (i)

Where, ΔU = change in internal energy for a process

q = heat

W = work

Given, q = + 701 J (Since heat is absorbed)

W = -394 J (Since work is done by the system)

Substituting the values in expression (i), we get

ΔU= 701 J + (-394 J) ΔU = 307 J

Hence, the change in internal energy for the given process is 307 J.

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