Class 11 Chemistry - Chapter Hydrocarbons NCERT Solutions | How do you account for the formation of
How do you account for the formation of ethane during chlorination of methane?
Chlorination of methane proceeds via a free radical chain mechanism. The whole reaction takes place in the given three steps.
Step 1: Initiation:
The reaction begins with the homolytic cleavage of Cl- Cl bond as:
Step 2: Propagation:
In the second step, chlorine free radicals attack methane molecules and break down the C- H bond to generate methyl radicals as:
These methyl radicals react with other chlorine free radicals to form methyl chloride along with the liberation of a chlorine free radical.
Hence, methyl free radicals and chlorine free radicals set up a chain reaction. While HCl and CH3Cl are the major products formed, other higher halogenated compounds are also formed as:
Step 3: Termination:
Formation of ethane is a result of the termination of chain reactions taking place as a result of the consumption of reactants as:
Hence, by this process, ethane is obtained as a by-product of chlorination of methane.
More Questions From Class 11 Chemistry - Chapter Hydrocarbons
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Addition of HBr to propene yields 2-bromopropane, while in the presence of benzoyl peroxide, the same reaction yields 1-bromopropane. Explain and give mechanism.
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Write IUPAC names of the products obtained by the ozonolysis of the following compounds:
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Why does benzene undergo electrophilic substitution reactions easily and nucleophilic substitutions with difficulty?
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Arrange benzene, n-hexane and ethyne in decreasing order of acidic behaviour. Also give reason for this behaviour.
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Explain why the following systems are not aromatic?
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Arrange the following set of compounds in order of their decreasing relative reactivity with an electrophile, E+
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