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Question 10

At 450K, Kp= 2.0 × 1010/bar for the given reaction at equilibrium.

2SO2(g) + O2(g) 2SO3 (g)

What is Kc at this temperature ?

Answer

For the given reaction,

Δn = 2 - 3 =-1

T = 450 K

R = 0.0831 bar L bar K-1 mol-1

Kp = 2.0 × 1010 bar -1

We know that,

Kp =  Kc (RT)Δn

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