Vapour pressure of pure water at 298 K is 23.8 mm Hg. 50 g of urea (NH2CONH2) is dissolved in 850 g of water. Calculate the vapour pressure of water for this solution and its relative lowering.
It is given that vapour pressure of water,PIo = 23.8 mm of Hg
Weight of water taken, w1= 850 g
Weight of urea taken, w2= 50 g
Molecular weight of water, M1= 18 g mol - 1
Molecular weight of urea, M2= 60 g mol - 1
Now, we have to calculate vapour pressure of water in the solution. We take vapour pressure as p1.
Now, from Raoult's law, we have:
Hence, the vapour pressure of water in the given solution is 23.4 mm of Hg and its relative lowering is 0.0173.
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(ii) Potassium tetracyanonickelate(II)
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(ii) Write IUPAC names of all the isomers.
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(i) α-Methoxypropionaldehyde
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(iii) 2-Hydroxycyclopentane carbaldehyde
(iv) 4-Oxopentanal
(v) Di-sec-butyl ketone
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(ii) Ethane to bromoethene
(iii) Propene to 1-nitropropane
(iv) Toluene to benzyl alcohol
(v) Propene to propyne
(vi) Ethanol to ethyl fluoride
(vii) Bromomethane to propanone
(viii) But-1-ene to but-2-ene
(ix) 1-Chlorobutane to n-octane
(x) Benzene to biphenyl.
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Write any two characteristics of Chemisorption.
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(ii) Hexanenitrile into 1-aminopentane
(iii) Methanol to ethanoic acid
(iv) Ethanamine into methanamine
(v) Ethanoic acid into propanoic acid
(vi) Methanamine into ethanamine
(vii) Nitromethane into dimethylamine
(viii) Propanoic acid into ethanoic acid
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(ii) Benzene into N, N-dimethylaniline
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Or practise isi type k numerical ki batana Nice method well
Answer is 23.1
Thanks uhhh
Ye answer book me nhi hai
Relative lowering kaise aaya
This is not the answer of my questions plz coelrrect it
Rlvp=p°1-p1/p°1= 23.8 -23.4/23.8= 0.4/23.8=0.0168 Rlvp =0.017(approx)
But the answer is 289.5 bar. Which is nentioned in 12th NCEET book.
Relative lowering kaise nikala vo bhi toh btao
vapour pressure in mm hg of 0.1 mole of urea in 180 g of water at 25 C is(the vapour pressure of water at 25 C is 24 mm hg)