Question 47

Neon gas is generally used in the sign boards. If it emits strongly at 616 nm, calculate

(a) the frequency of emission,

(b) distance traveled by this radiation in 30 s

(c) energy of quantum and

(d) number of quanta present if it produces 2 J of energy.

Answer

λ = 616nm  or = 616x10-9m

a) Frequency , v=c/ λ = 3.8x10/ 616x10-9 = 4.87x1014 s-1

b) Velocity of the radiation = 3x10m/s

Therefore distance travelled in 30s = 30x3x108 = 9.0x109m

c) E = hv = hc/ λ = (6.626x10-34)(3.0x108) / (616x10-9 ) = 32.27x10-20J

d) No of quanta in 2J of energy = 2/32.27 x 10-28 = 6.2x1018

Popular Questions of Class 11 Chemistry

10 Comment(s) on this Question

Write a Comment: