Calculate the mass of sodium acetate (CH | Class 11 Chemistry Chapter Some Basic Concepts of Chemistry, Some Basic Concepts of Chemistry NCERT Solutions

Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter Some Basic Concepts of Chemistry. This page offers a step-by-step solution to the specific question from Exercise 1, Question 5: . With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.

Question 5:

Calculate the mass of sodium acetate (CH3COONa) required to make 500 mL of 0.375 molar aqueous solution. Molar mass of sodium acetate is 82.0245 g mol–1

Answer:

0.375 M solution of (CH3COONa) = 0.375 moles(grams) of (CH3COONa) dissolved in 1000 ml of solvent.

 

But according to question ,we have to make a 500 ml solution of (CH3COONa)

 

∴Number of moles of sodium acetate in 500 mL

 

 

Molar mass of sodium acetate = 82.0245 g mole–1 (Given)

 

∴ Required mass of sodium acetate = (82.0245 g mol–1) (0.1875 mole)

 

= 15.38 g

 

 


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Comments

  • Ridham Patel
  • May 29, 2020

Thank you


  • Tanu
  • May 24, 2020

Thanks a lot


  • Adi
  • Jul 21, 2019

Thanks for elaboration


  • Indranil
  • Jul 09, 2019

Thanks


  • Saumya
  • Jul 07, 2019

thanks for such good explanation


  • Prasoon
  • Jun 30, 2019

Supriti try to love


  • ravi
  • Jun 23, 2019

thnx


  • ravi
  • Jun 23, 2019

thanx


  • Sahil
  • Jun 18, 2019

Why we multi. 82.0245 with 0.1875 not divede


  • sakshi
  • Jun 05, 2019

Thank you but I want it a little more briefly


Add Comment

Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 5: Calculate the mass of sodium acetate (CH3COONa) required to make 500 mL of 0.375 molar aqueous solut....