Explain the formation of H2 molecule on | Class 11 Chemistry Chapter Chemical Bonding and Molecular Structure, Chemical Bonding and Molecular Structure NCERT Solutions

Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter Chemical Bonding and Molecular Structure. This page offers a step-by-step solution to the specific question from Exercise 1, Question 33: . With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.

Question 33:

Explain the formation of H2 molecule on the basis of valence bond theory.

Answer:

When hydrogen atoms combine to form molecules of hydrogen, 433 KJ/mol. energy is released.

Whenever atoms combine to form a molecule, there is always decrease in the energy. Actually, when two H atoms are far separated, they do not have any force of interaction (attractive or repulsive). As they tend to come closer, two different forces operates:

(a) The nucleus of one H is attracted towards the electrons of the other H atoms and Vice-versa. The energy is released in attraction.

(b) The nuclei of the atoms as well as their electrons repel each other. Energy is needed to overcome the force of repulsion.

Now in case, if the magnitude of the attractive forces is more than that of the repulsive forces, a stable molecule will be formed.

However, if the repulsive forces are more than the attractive forces, then the atoms will not combine.

If for example HA & HB are two hydrogen atoms & eA & eB are their respective electrons, then attractive & repulsive forces may be shown as follows:

 

                                                         ------------ old attractive forces

                                           _________ new attractive forces

The number of new attractive and repulsive forces is same, but the magnitude of attractive forces is more. Thus, when two hydrogen atoms approach each other, the overall potential energy decreases, hence a stable hydrogen molecule is formed.


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  • Read the question carefully and focus on the core concept being asked.
  • Reference examples and data from the chapter when answering questions about Chemical Bonding and Molecular Structure.
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Comments

  • imdad
  • Nov 13, 2019

Thank you so much 😊


  • Sejal
  • Sep 09, 2019

It's very helpful and explanable one also ...thanks


  • Shiv Nandan Kumar Rana
  • Aug 02, 2019

Ncert ka copy paste kar k hero banta hai, loll😆😆😆😆😆😆😆😆


  • Baiju kumar jha
  • Feb 21, 2019

Helpful answer


  • Aniruddh Jat
  • Dec 17, 2018

Bhadiya


  • Himani
  • Nov 29, 2018

Thanks


  • Divya
  • Aug 26, 2018

Best answer


  • Zohaib
  • Jul 15, 2018

Professional work !!


  • Shivee jaiswal
  • Jun 23, 2018

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  • Prabhjot singh
  • Apr 03, 2018

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Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 33: Explain the formation of H2 molecule on the basis of valence bond theory.....