Class 12th Physics 2017 Set3 Delhi Board Paper Solution
A monochromatic light of wavelength 500 nm is incident normally on a single slit of width 0.2 mm to produce a diffraction pattern. Find the angular width of the central maximum obtained on the screen.
Estimate the number of fringes obtained in Young's double slit experiment with fringe width 0.5 mm, which can be accommodated within the region of total angular spread of the central maximum due to single slit.
Angular width of central maximum in diffraction pattern:
= 2λ / d = 2 x 500 x 10-9 / 0.2 x 10-3
= 0.5 x 10-3 m for double slit
Number of fringes = Angular width / Fringe width = 5 x 10-3 / 0.5 x 10-3 = 10 fringes
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