A regular hexagon of side 10 cm has a charge 5 µC at each of its vertices. Calculate the potential at the centre of the hexagon.
The given figure shows six equal amount of charges, q, at the vertices of a regular hexagon.
Where, Charge, q = 5 µC = 5 × 10- 6 C
Side of the hexagon, l = AB = BC = CD = DE = EF = FA = 10 cm
Distance of each vertex from centre O, d = 10 cm
Electric potential at point O,
Where,
= Permittivity of free space
Therefore, the potential at the centre of the hexagon is 2.7 × 106 V.
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Thanks and very nice
@nishma_ for a regular hexagon the internal angles are 60 degrees each which makes 6 equilateral triangle s inside the hexagon.
l have adoubt that how the distance from cetre to each vertices is10cm