A polythene piece rubbed with wool is found to have a negative charge of 3 × 10−7 C.
(a) Estimate the number of electrons transferred (from which to which?)
(b) Is there a transfer of mass from wool to polythene?
(a) When polythene is rubbed against wool, a number of electrons get transferred from wool to polythene. Hence, wool becomes positively charged and polythene becomes negatively charged.
Amount of charge on the polythene piece, q = −3 × 10−7 C
Amount of charge on an electron, e = −1.6 × 10−19 C
Number of electrons transferred from wool to polythene = n
n can be calculated using the relation, q = ne
=
= 1.87 × 1012
Therefore, the number of electrons transferred from wool to polythene is 1.87 × 1012.
(b) Yes. There is a transfer of mass occur. This is because an electron has mass,
as we know
me = 9.1 × 10−3 kg
Total mass transferred from wool to polythene,
m = me × n
= 9.1 × 10−31 × 1.85 × 1012
= 1.706 × 10−18 kg
Hence, a negligible amount of mass is transferred from wool to polythene.
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(a) What is the distance between the two spheres?
(b) What is the force on the second sphere due to the first?
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(a) A charge q is placed at the centre of the shell. What is the surface charge density on the inner and outer surfaces of the shell?
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R1 = 10 Ω, N1 = 30,
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(b) Obtain the displacement current across the plates.
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Thanks
Thank you, I got it ð
me = 9.1 Ã 10â3 kg y sahi hai
How u get Me value there
I sincerely apologise to have given an incorrect comment previously. Regards.
There's also a part (c) in the question. Please check. Regards
Its totally wrong
no due to wrong multiplication
nooooo
Why is n is having a fractional value when \'n\' must always be a whole number according to quantization theory? Please explain the fault in the numerical.