Question 14

If the bar magnet in exercise 5.13 is turned around by 180º, wherewill the new null points be located?


The magnetic field on the axis of the magnet at a distance d1= 14 cm, can be written as:

Where, M = Magnetic moment

μ0= Permeability of free space

H= Horizontal component of the magnetic field at d1

If the bar magnet is turned through 180°, then the neutral point will lie on the equatorial line.

Hence, the magnetic field at a distance d2, on the equatorial line of the magnet can be written as:

Equating equations (1) and (2), we get:

The new null points will be located 11.1 cm on the normal bisector.

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