Question 11

A 600 pF capacitor is charged by a 200 V supply. It is then disconnected from the supply and is connected to another uncharged 600 pF capacitor. How much electrostatic energy is lost in the process?


Capacitance of the capacitor, C = 600 pF

Potential difference, V = 200 V

Electrostatic energy stored in the capacitor is given by,

If supply is disconnected from the capacitor and another capacitor of capacitance C = 600 pF is connected to it, then equivalent capacitance (C') of the combination is given by,

New electrostatic energy can be calculated as

Loss in electrostatic enegy = E - E'

                                        = 1.2 x 10-5  -  0.6 x 10-5

                                        = 0.6 x 10-5

                                        = 6 x 10-6

Therefore, the electrostatic energy lost in the process is 6 x 10-6 J.  

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