Question 18

A point charge +10 μC is a distance 5 cm directly above the centre of a square of side 10 cm, as shown in Fig. 1.34. What is the magnitude of the electric flux through the square? (Hint: Think of the square as one face of a cube with edge 10 cm.)

Answer

The square can be considered as one face of a cube of edge 10 cm with a centre where charge q is placed. According to Gauss’s theorem for a cube, total electric flux is through all its six faces.

Hence, electric flux through one face of the cube i.e., through the square,

Where, ∈0 = Permittivity of free space

= 8.854 × 10^{−12} N^{−1}C^{2} m^{−2} q = 10 μC = 10 × 10^{−6} C

∴

= 1.88 × 10^{5} N m^{2} C^{−1}

Therefore, electric flux through the square is 1.88 × 10^{5} N m^{2} C^{−1}.

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- Q:-
A short bar magnet of magnetic moment m = 0.32 JT

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SPBhagyam
2020-07-30 20:28:32

Thakzzz

SPBhagyam
2020-07-30 20:27:56

Gud

Anamika
2019-11-24 15:34:39

Thnq Ã°ÂŸÂ˜ÂŠ

Pratisha
2019-06-18 22:30:02

Can we solve this without using Gauss law?? ( By using EdScos0 alone)

Arvendra dhakar
2018-12-25 07:29:22

Thanks a lot

Shivangi srivastava
2018-07-01 12:04:54

Thanks

Miracle
2017-06-16 13:41:37

Two charges q1= 10uc and q2= -12uc are within a spherical surface of radius 10cm. What is the total flux through the surface ?

Harsh
2017-04-22 13:09:50

Nice

Student
2017-04-16 11:13:19

Thanks a lot

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