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Class 12th Physics 2018 Set1 Delhi Board Paper Solution

Question 6

Two Electric bulbs P and Q have their resistances in the ratio of 1:2. They are connected in series across a battery. Find the ratio of the power dissipation in these bulbs.


Let ratio be x

Rp  = x  (Resistance of bulb P)

Rq = 2x (Resistance of bulb Q)

as, P = VI = V. V / R

Pp / Pq  =   V2  /  Rp   x  Rq / V2      [In series potential will be same]

Pp / Pq  =  2x / x = 2 : 1

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