The pH of milk, black coffee, tomato juice, lemon juice and egg white are 6.8, 5.0, 4.2, 2.2 and 7.8 respectively. Calculate corresponding hydrogen ion concentration in each.
The hydrogen ion concentration in the given substances can be calculated by using the given relation:
pH = -log [H+]
(i) pH of milk = 6.8
Since, pH = -log [H+]
6.8 = -log [H+]
log [H+] = -6.8
[H+] = anitlog(-6.8)
= 1.5x10-7M
(ii) pH of black coffee = 5.0
Since, pH = -log [H+]
5.0 = -log [H+]
log [H+] = -5.0
[H+] = anitlog(-5.0)
= 10-5M
(iii) pH of tomato juice = 4.2
Since, pH =-log [H+]
4.2 =-log [H+]
log [H+] = -4.2
[H+] = anitlog(-4.2)
= 6.31x10-5M
(iv) pH of lemon juice = 2.2
Since, pH = -log [H+]
2.2 = -log [H+]
log [H+] = -2.2
[H+] = anitlog(-2.2)
=6.31x10-3M
(v) pH of egg white = 7.8
Since, pH = -log [H+]
7.8 = -log[H+]
log[H+] = -7.8
[H+] = anitlog(-7.8)
= 1.58x10-8M
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(ii) 1 mole of carbon is burnt in 16 g of dioxygen.
(iii) 2 moles of carbon are burnt in 16 g of dioxygen.
Calculate the wavelength of an electron moving with a velocity of 2.05 × 107 ms–1.
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(a) MnO4 – (aq) + I – (aq) → MnO2 (s) + I2(s) (in basic medium)
(b) MnO4 – (aq) + SO2 (g) → Mn2+ (aq) + HSO4– (aq) (in acidic solution)
(c) H2O2 (aq) + Fe 2+ (aq) → Fe3+ (aq) + H2O (l) (in acidic solution)
(d) Cr2O7 2– + SO2(g) → Cr3+ (aq) + SO42– (aq) (in acidic solution)
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(i) 300 atoms of A + 200 molecules of B
(ii) 2 mol A + 3 mol B
(iii) 100 atoms of A + 100 molecules of B
(iv) 5 mol A + 2.5 mol B
(v) 2.5 mol A + 5 mol B
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(i) 1 g Au (s)
(ii) 1 g Na (s)
(iii) 1 g Li (s)
(iv) 1 g of Cl2(g)
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(a) P4(s) + OH – (aq) → PH3(g) + HPO2 – (aq)
(b) N2H4(l) + ClO3 – (aq) → NO(g) + Cl–(g)
(c) Cl2O7 (g) + H2O2(aq) → ClO – 2(aq) + O2(g) + H + (aq)
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Mass of dinitrogen Mass of dioxygen
(i) 14 g 16 g
(ii) 14 g 32 g
(iii) 28 g 32 g
(iv) 28 g 80 g
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(i) 1 km = ...................... mm = ...................... pm
(ii) 1 mg = ...................... kg = ...................... ng
(iii) 1 mL = ...................... L = ...................... dm3
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(i) 300 atoms of A + 200 molecules of B
(ii) 2 mol A + 3 mol B
(iii) 100 atoms of A + 100 molecules of B
(iv) 5 mol A + 2.5 mol B
(v) 2.5 mol A + 5 mol B
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