Question 8

What will be the pressure of the gaseous mixture when 0.5 L of H2 at 0.8 bar and 2.0 L of dioxygen at 0.7 bar are introduced in a 1L vessel at 27°C?

Answer

From the equation Pv = n RT for the two gases. We can write

0.8 x 0.5 = nH2 x RT  or nH2  = 0.8 x 0.5 / RT

ALSO  0.7 x 2.0  = n02 . RT  or n02  = 0.7 x 2 / RT

When introduced in 1 L vessel, then

Px1L = (n02 + nH2)  RT

Putting the values, we get

P = 0.4 + 1.4 = 1.8 bar

Hence, the total pressure of the gaseous mixture in the vessel is 1.8 bar

Popular Questions of Class 11 Chemistry

Recently Viewed Questions of Class 11 Chemistry

5 Comment(s) on this Question

Write a Comment: