Calculate the total pressure in a mixture of 8 g of dioxygen and 4 g of dihydrogen confined in a vessel of 1 dm3 at 27°C. R = 0.083 bar dm3 K–1 mol–1.
Given,
Mass of oxygen = 8 g, molar mass of oxygen = 32 g/mol
Mass of hydrogen = 4 g, molar mass of hydrogen = 2 g/mol
Therefore amount of oxygen = 8/ 32 = 0.25 mol
And amount of hydrogen = 4/2 = 2 mol
From the gas equation PV = n RT, we get,
P X 1 = (0.25 + 2) X 0.083 X 300 = 56.02 bar
Hence, the total pressure of the mixture is 56.02 bar.
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