# Class 11 Chemistry States of Matter: NCERT Solutions for Question 12

This page focuses on the detailed States of Matter question answers for Class 11 Chemistry States of Matter, addressing the question: 'Calculate the temperature of 4.0 mol of a gas occupying 5 dm3 at 3.32 bar. (R = 0.083 bar dm3 K–1 mol–1).'. The solution provides a thorough breakdown of the question, highlighting key concepts and approaches to arrive at the correct answer. This easy-to-understand explanation will help students develop better problem-solving skills, reinforcing their understanding of the chapter and aiding in exam preparation.
Question 12

## Calculate the temperature of 4.0 mol of a gas occupying 5 dm3 at 3.32 bar.(R = 0.083 bar dm3 K–1 mol–1).

Given,

Amount of the gas, n = 4.0 mol

Volume of the gas, V = 5 dm3

Pressure of the gas, p = 3.32 bar

R = 0.083 bar dm3 K–1 mol–1

From the ideal gas equation, we get

pV = nRT

T = pV / nR

= (3.32x5) /  (4x0.083)

= 50K

Hence, the required temperature is 50 K.