Question 10

Determine order and degree(if defined) of differential equation y^{n} + 2y^{'} + siny = 0

Answer

y^{n} + 2y^{'} + siny = 0

The highest order derivative present in the differential equation is y^{n}. Therefore, its order is two.

This is a polynomial equation in y^{n }and y' and the highest power raised to y^{n }is one. Hence, its degree is one.

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