
Q1 Given that E and F are events such that P(E) = 0.6, P(F) = 0.3 and P(E ∩ F) = 0.2, find P (EF) and P(FE).
Ans: It is given that P(E) = 0.6, P(F) = 0.3, and P(E ∩ F) = 0.2
In this chapter, we will learn some new aspects of probability like conditional probability etc. All the concepts which we have studied in previous classes will help us in understanding these new topics in a better way. Topics which are included in this chapter  conditional probability, multiplication theorem on probability, independent events, Bayes theorem, total probability, random variable and its probability distribution, mean and variance, Binomial distribution.
Download pdf of NCERT Solutions for Class Mathematics Chapter 13 Probability
Download pdf of NCERT Examplar with Solutions for Class Mathematics Chapter 13 Probability
Q1  Given that E and F are events such that P(E) = 0.6, P(F) = 0.3 and P(E ∩ F) = 0.2, find P (EF) and P(FE). 
Ans:  It is given that P(E) = 0.6, P(F) = 0.3, and P(E ∩ F) = 0.2 
Prove that the Greatest Integer Function f : R → R, given by f(x) = [x], is neither oneone nor onto, where [x] denotes the greatest integer less than or equal to x.
Check the injectivity and surjectivity of the following functions:
(i) f : N → N given by f(x) = x^{2}
(ii) f : Z → Z given by f(x) = x^{2}
(iii) f : R → R given by f(x) = x^{2}
(iv) f : N → N given by f(x) = x^{3}
(v) f : Z → Z given by f(x) = x^{3 }
Show that the Modulus Function f : R → R, given by f(x) = x, is neither oneone nor onto, where  x  is x, if x is positive or 0 and x is – x, if x is negative.
Let A = {1, 2, 3}, B = {4, 5, 6, 7} and let f = {(1, 4), (2, 5), (3, 6)} be a function from A to B. Show that f is oneone.
Consider f : R → R given by f(x) = 4x + 3. Show that f is invertible. Find the inverse of f.
Let f : R → R be defined as f(x) = x^{4}. Choose the correct answer.
(A) f is oneone onto
(B) f is manyone onto
(C) f is oneone but not onto
(D) f is neither oneone nor onto.