Class 12 Mathematics - Chapter Application of Derivatives NCERT Solutions | Find the rate of change of the area of a
Find the rate of change of the area of a circle with respect to its radius r when
(a) r = 3 cm
(b) r = 4 cm
The area of a circle (A) with radius (r) is given by,
A = πr2
Now, the rate of change of the area with respect to its radius is given by,
\begin{align} \frac{dA}{dr} = \frac{d}{dr}(πr^2) = 2πr \end{align}
- When r = 3 cm,
\begin{align} \frac{dA}{dr} = 2π (3) = 6π \end{align}
Hence, the area of the circle is changing at the rate of 6π cm2/s when its radius is 3 cm.
- When r = 4 cm,
\begin{align} \frac{dA}{dr} = 2π (4) = 8π \end{align}
Hence, the area of the circle is changing at the rate of 8π cm2/s when its radius is 4 cm.
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