
Q1 Maximise Z = 3x + 4y Subject to the constraints:x + y ≤ 4, x ≥ 0, y ≥ 0 Ans: The feasible region determined by the constraints, x + y ≤ 4, x ≥ 0, y ≥ 0, is as follows.
The corner points of the feasible region are O (0, 0), A (4, 0), and B (0, 4). The values of Z at these points are as follows.
Corner point
Z = 3x + 4y
O(0, 0)
0
A(4, 0)
12
B(0, 4)
16
→ Maximum
Therefore, the maximum value of Z is 16 at the point B (0, 4).