Class 11 Chemistry Classification of Elements and Periodicity in Properties: NCERT Solutions for Question 36

This page focuses on the detailed Classification of Elements and Periodicity in Properties question answers for Class 11 Chemistry Classification of Elements and Periodicity in Properties, addressing the question: 'The size of isoelectronic species — F–, Ne and Na+ is affected by (a) Nuclear charge (Z ) (b) Valence principal quantum number (n) (c) Electron-electron interaction in the outer orbitals (d) None of the factors because their size is the same.'. The solution provides a thorough breakdown of the question, highlighting key concepts and approaches to arrive at the correct answer. This easy-to-understand explanation will help students develop better problem-solving skills, reinforcing their understanding of the chapter and aiding in exam preparation.
Question 36

The size of isoelectronic species — F, Ne and Na+ is affected by

(a) Nuclear charge (Z )

(b) Valence principal quantum number (n)

(c) Electron-electron interaction in the outer orbitals

(d) None of the factors because their size is the same.

Answer

Isoelectronic species are the species belonging to different atoms or ions which have same number of electrons but different magnitudes of nuclear charges.

The size of an isoelectronic species increases with a decrease in the nuclear charge (Z). For example, the order of the increasing nuclear charge of F-, Ne, and Na+ is as follows:

F- < Ne < Na+

Z     9     10     11

Therefore, the order of the increasing size of F-, Ne and Na+ is as follows:

Na+ < Ne < F-

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