If the speed of light is 3.0 × 108 ms–1, calculate the distance covered by light in 2.00 ns.
According to the question:
Time taken to cover the distance = 2.00 ns
= 2.00 × 10–9 s
Speed of light = 3.0 × 108 ms–1
We know speed = distance/time
Or distance = speed x time
Therefore Distance travelled by light in 2.00 ns
= Speed of light × Time taken
= (3.0 × 108 ms –1) (2.00 × 10–9 s)
= 6.00 × 10–1 m
= 0.600 m
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Thanks for confirmation
What is ns here?
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