The work function for caesium atom is 1. | Class 11 Chemistry Chapter Structure of Atom, Structure of Atom NCERT Solutions

Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter Structure of Atom. This page offers a step-by-step solution to the specific question from Exercise 1, Question 51: . With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.

Question 51:

The work function for caesium atom is 1.9 eV. Calculate

(a) the threshold wavelength and

(b) the threshold frequency of the radiation. If the caesium element is irradiated with a wavelength 500 nm, calculate the kinetic energy and the velocity of the ejected photoelectron.

Answer:

A) Work function of caesium (WO) = hvo

Therefore vo = WO/h = 1.9 x1.602 x10-19 / 6.626x10-34

= 4.59x1014/sec

 

B) λo =c/vo = 3x10/ 4.59x1014 = 6.54x10-7m

 

C) K.E of ejected electron = h(v-vo) = hc(1/λ – 1/ λo)

=(6.626x3x10-26) (1/500x10-9 – 1/654x10-9)

=(6.626x3x10-26) / 10-9(154/500x654)

= 9.36x10-20J

k.E = 1mv2/2 = 9.36x10-20J

=9.1x10-31/2 = 9.36x10-20J

Or

v2 = 20.55x1010m2s-2

Or

v = 4.53x105ms-1


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Comments

  • Vansh
  • Dec 19, 2019

Part 1st ka ans second wala h and vice versa


  • Jash
  • Jul 28, 2019

Thanks for providing the ans .😀😃


  • Mayukh
  • May 24, 2019

A really smart answer!


  • Khushi
  • Jan 24, 2019

It's very helpful thanks....


  • Garvit
  • Jul 10, 2018

Galat h


  • renu
  • Jul 06, 2018

Thanks for helping us


  • vijayvijay
  • Jun 16, 2018

thanks for helping me


  • Khatri
  • May 27, 2018

Nyc solution


  • Rakshan
  • Aug 03, 2017

Bakwas


  • MHYT
  • Jun 15, 2017

its really helpfull.thank u


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Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 51: The work function for caesium atom is 1.9 eV. Calculate (a) the threshold wavelength and (b) t....