Question 9

Find the sum to n terms in the geometric progression 1,-a, a2,-a3, ... (if a  -1)

Answer

The given G.P. is 1,-a, a2,-a3, .........

Here, first term = a1 = 1

Common ratio = r = – a

S subscript n equals fraction numerator a subscript 1 open parentheses 1 minus r to the power of n close parentheses over denominator 1 minus r end fraction
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S subscript n equals fraction numerator 1 open square brackets 1 minus open parentheses minus a close parentheses to the power of n close square brackets over denominator 1 minus open parentheses minus a close parentheses end fraction space equals space fraction numerator open square brackets 1 minus open parentheses minus a close parentheses to the power of n close square brackets over denominator 1 plus a end fraction

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