Class 12 Chemistry - Chapter Electrochemistry NCERT Solutions | The molar conductivity of 0.025 mol L-1
The molar conductivity of 0.025 mol L-1 methanoic acid is
46.1 S cm2 mol-1.
Calculate its degree of dissociation and dissociation constant. Given λ0(H+)
= 349.6 S cm2 mol-1 and λ0(HCOO-) = 54.6 S cm2 mol
C = 0.025 mol L - 1
Now, degree of dissociation:
Thus, dissociation constant:
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