A geyser heats water flowing at the rate of 3.0 litres per minute from 27 °C to 77 °C. If the geyser operates on a gas burner, what is the rate of consumption of the fuel if its heat of combustion is 4.0 x 104 J/g?
Water is flowing at a rate of 3.0 litre/min.
The geyser heats the water, raising the temperature from 27°C to 77°C.
Initial temperature, T1 = 27°C
Final temperature, T2 = 77°C
∴Rise in temperature, ΔT = T2 - T1 = 77 - 27= 50°C
Heat of combustion = 4 × 104 J/g
Specific heat of water, c = 4.2 J g-1 °C-1
Mass of flowing water, m = 3.0 litre/min = 3000 g/min
Total heat used, ΔQ = mc ΔT
= 3000 × 4.2 × 50
= 6.3 × 105 J/min
∴Rate of consumption = = 15.75 g/min
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(b) work done by gravitational force in the above case,
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(b) climbs down with an acceleration of 4 m s-2
(c) climbs up with a uniform speed of 5 m s-1
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(Ignore the mass of the rope).
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(c) λ / 2 ,
(d) 3λ / 4
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