The ionization constant of acetic acid i | Class 11 Chemistry Chapter Equilibrium, Equilibrium NCERT Solutions

Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter Equilibrium. This page offers a step-by-step solution to the specific question from Exercise 1, Question 46: . With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.

Question 46:

The ionization constant of acetic acid is 1.74 x 10-5. Calculate the degree of dissociation of acetic acid in its 0.05 M solution. Calculate the concentration of acetate ion in the solution and its pH.

Answer:

1) CH3COOH        CH3COO-  + H+     Ka = 1.74x10-5

2) H2O + H2O       H3O+   +   OH-        Kw  = 1.0x10-14

Since Ka > Kw

         CH3COOH  + H2O       CH3COO-  +    H3O+

Ci  =  0.05                                     0                   0

       0.05- 0.05α                     0.05α             0.05α  

ka =  0.05α x   0.05α  /   0.05- 0.05α  

= 0.05α x   0.05α  /   0.05 (1-α)

= 0.05α2  /  (1-α)

⇒ 1.74x10-5  =  0.05α2  /  (1-α)

⇒ 1.74x10-5   -  1.74x10-5 α  =  0.05α2 

⇒ 0.05α2  +    1.74x10-5 α  -  1.74x10-5 =0

D =  b2 - 4ac

   = (1.74x10-5 )2 - 4 (0.05) (1.74x10-5)

   = 3.02x10-25  + 0.348x10-5

Method 2:

Degree of Dissociation,

CH3COOH      CH3COO- + H+

Thus, concentration of CH3COO- = c.α 

= 0.05x1.86x10-2

= 0.93x10-2

=.00093M

Since [oAc-] = [H+]

[H+] = .00093 = 0.093x10-2

pH = -log[H+]

     =  -log (0.93x10-2)

∴ pH = 3.03

Hence, the concentration of acetate ion in the solution is 0.00093 M and its Ph is 3.03.

 


Study Tips for Answering NCERT Questions:

NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:

  • Read the question carefully and focus on the core concept being asked.
  • Reference examples and data from the chapter when answering questions about Equilibrium.
  • Review previous year question papers to get an idea of how such questions may be framed in exams.
  • Practice answering questions within the time limit to improve your speed and accuracy.
  • Discuss your answers with your teachers or peers to get feedback and improve your understanding.

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Comments

  • Swarnendu Bhowmick
  • Mar 19, 2019

Excellent advice


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Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 46: The ionization constant of acetic acid is 1.74 x 10-5. Calculate the degree of dissociation of aceti....