Question 16

(i) The energy associated with the first orbit in the hydrogen atom is –2.18 × 10–18 J atom–1. What is the energy associated with the fifth orbit?

(ii) Calculate the radius of Bohr’s fifth orbit for hydrogen atom.

Answer

Energy of an electrons = -(2.18x 10-18)/n2

Where n= principal quantum number

Now the Energy associated with the fifth orbit of hydrogen atom is

\begin{align}E_{5}=\frac{-(2.18\times10^{-18})}{(5)^{2}}=\frac{-2.18\times10^{-18}}{25}\end{align}

                                E5 = –8.72 × 10–20 J

 

(ii) Radius of Bohr’s nth orbit for hydrogen atom is given by,

rn = (0.0529 nm) n2

For,

n = 5

r5 = (0.0529 nm) (5)2

r5 = 1.3225 nm

 

 

 

 

 

 

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