Two towns A and B are connected by a reg | Class 11 Physics Chapter Motion in a straight Line, Motion in a straight Line NCERT Solutions

Welcome to the NCERT Solutions for Class 11 Physics - Chapter Motion in a straight Line. This page offers a step-by-step solution to the specific question from Exercise 1, Question 9: . With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.

Question 9:

Two towns A and B are connected by a regular bus service with a bus leaving in either direction every T minutes. A man cycling with a speed of 20 km h–1 in the direction A to B notices that a bus goes past him every 18 min in the direction of his motion, and every 6 min in the opposite direction. What is the period T of the bus service and with what speed (assumed constant) do the buses ply on the road?

Answer:

Let V be the speed of the bus running between towns A and B.

Speed of the cyclist, v = 20 km/h

Relative speed of the bus moving in the direction of the cyclist

= V – v = (V – 20) km/h

The bus went past the cyclist every 18 min i.e. 18/60 h, (when he moves in the direction of the bus).

Distance covered by the bus = (V - 20) 18/60………….. (i)

Since one bus leaves after every T minutes, the distance travelled by the bus will be equal to:

 V x T/60       .............(ii)

Both equations (i) and (ii) are equal.

(V - 20) x 18/60   =  VT / 60  .............. (iii)

Relative speed of the bus moving in the opposite direction of the cyclist = (V + 20) km/h

Time taken by the bus to go past the cyclist = 6 min  = 6/60 h

∴(V - 20) x 6/60   =  VT / 60              ................ (iv)

From equations (iii) and (iv), we get

(V - 20) x 6/60   =  (V - 20) x 18/60 

V - 20  =   3V - 60

2V  = 80

V  = 40 km/h

Substituting the value of V in equation (iv), we get

(40+20) x 6/60  = 40T/60

60 x 6/60  = 40T/60

6 = 40T/60

⇒ 40T  = 6x60

⇒ 40T  = 360

⇒   T  = 360/40

⇒   T  =  9 min


Study Tips for Answering NCERT Questions:

NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:

  • Read the question carefully and focus on the core concept being asked.
  • Reference examples and data from the chapter when answering questions about Motion in a straight Line.
  • Review previous year question papers to get an idea of how such questions may be framed in exams.
  • Practice answering questions within the time limit to improve your speed and accuracy.
  • Discuss your answers with your teachers or peers to get feedback and improve your understanding.

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Welcome to the NCERT Solutions for Class 11 Physics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 9: Two towns A and B are connected by a regular bus service with a bus leaving in either direction ever....