Question 20

A point charge causes an electric flux of −1.0 × 10^{3} Nm^{2}/C to pass through a spherical Gaussian surface of 10.0 cm radius centered on the charge.

(a) If the radius of the Gaussian surface were doubled, how much flux would pass through the surface?

(b) What is the value of the point charge?

Answer

(a) Electric flux, Φ = −1.0 × 10^{3} N m^{2}/C

Radius of the Gaussian surface,

r = 10.0 cm

Electric flux piercing out through a surface depends on the net charge enclosed inside a body. It does not depend on the size of the body. If the radius of the Gaussian surface is doubled, then the flux passing through the surface remains the same i.e., −10^{3} N m^{2}/C.

(b) Electric flux is given by the relation,

Where, q = Net charge enclosed by the spherical surface

∈_{0} = Permittivity of free space = 8.854 × 10^{−12} N^{−1}C^{2} m^{−2}

∴

= −1.0 × 10^{3} × 8.854 × 10^{−12}

= −8.854 × 10^{−9} C

= −8.854 nC

Therefore, the value of the point charge is −8.854 nC.

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Sai
2019-12-13 22:36:52

thanks a lot

parth
2019-06-22 21:31:48

thnks for help

Xyz
2018-12-24 23:19:23

It helped me..so thanks..âºð

harsha
2018-05-09 13:17:57

It's great. Tysm for making it really Saral.....

shatakshi
2018-03-20 00:12:19

thanks a lot

sloth
2016-01-07 10:34:19

Thank you so g-- damn much. I had no idea what I was doing until I stumbled across this. You have no idea.

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