Welcome to the Chapter 6 - Electromagnetic Induction, Class 12 Physics NCERT Solutions page. Here, we provide detailed question answers for Chapter 6 - Electromagnetic Induction. The page is designed to help students gain a thorough understanding of the concepts related to natural resources, their classification, and sustainable development.
Our solutions explain each answer in a simple and comprehensive way, making it easier for students to grasp key topics Electromagnetic Induction and excel in their exams. By going through these Electromagnetic Induction question answers, you can strengthen your foundation and improve your performance in Class 12 Physics. Whether you’re revising or preparing for tests, this chapter-wise guide will serve as an invaluable resource.
Length of the rectangular wire, l = 8 cm = 0.08 m
Width of the rectangular wire, b = 2 cm = 0.02 m
Hence, area of the rectangular loop,
A = lb
= 0.08 × 0.02
= 16 × 10−4 m2
Magnetic field strength, B = 0.3 T
Velocity of the loop, v = 1 cm/s = 0.01 m/s
(a) Emf developed in the loop is given as:
e = Blv
= 0.3 × 0.08 × 0.01 = 2.4 × 10−4 V
Time taken to travel along the width , t = Distance traveled / Velocity = b / v
Hence, the induced voltage is 2.4 × 10−4 V which lasts for 2 s.
(b) Emf developed, e = Bbv
= 0.3 × 0.02 × 0.01 = 0.6 × 10−4 V
Hence, the induced voltage is 0.6 × 10−4 V which lasts for 8 s.
The Electromagnetic Induction is an important chapter of 12 Physics. This chapter’s important topics like Electromagnetic Induction are often featured in board exams. Practicing the question answers from this chapter will help you rank high in your board exams.
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