Question 26

Is there any change in the hybridisation of B and N atoms as a result of the following reaction?

BF3 + NH3 → F3B.NH3

 

Answer

The atomic number of boron is 5 & its electronic configuration in ground state  is 1s2 2s2 2p1, & in excited state is 1s2 2s1 2p2 , this means its one s & 2 p orbital will take part in hybridization to form sp2  hybrid orbital.



Similarly N atom has atomic number of 7, with electronic configuration of 1s2 2s2 2p3 in its ground state & in it excited state it has sp3 hybridization.

Now according to the question Boron & Nitrogen in reactant stage has sp2 & sp3  hybridization respectively, but on the product side an adduct is formed, wherein Boron has changed it s hybridization to sp3 while Nitrogen remains in same sp3 hybridization

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