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Question 5

Write the Nernst equation and emf of the following cells at 298 K:

(i) Mg(s) | Mg2+(0.001M) || Cu2+(0.0001 M) | Cu(s)

(ii) Fe(s) | Fe2+(0.001M) || H+(1M)|H2(g)(1bar) | Pt(s)

(iii) Sn(s) | Sn2+(0.050 M) || H+(0.020 M) | H2(g) (1 bar) | Pt(s)

(iv) Pt(s) | Br2(l) | Br-(0.010 M) || H+(0.030 M) | H2(g) (1 bar) | Pt(s).

Answer

(i) For the given reaction, the Nernst equation can be given as:

= 2.7 - 0.02955 = 2.67 V (approximately)

 

(ii) For the given reaction, the Nernst equation can be given as:

= 0.52865 V = 0.53 V (approximately)

 

(iii) For the given reaction, the Nernst equation can be given as:

= 0.14 - 0.0295 × log125

= 0.14 - 0.062

= 0.078 V

= 0.08 V (approximately)

 

(iv) For the given reaction, the Nernst equation can be given as:

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