Class 12 Chemistry - Chapter Solutions NCERT Solutions | The air is a mixture of a number of gase
The air is a mixture of a number of gases. The major components are oxygen and nitrogen with approximate proportion of 20% is to 79% by volume at 298 K. The water is in equilibrium with air at a pressure of 10 atm. At 298 Kif the Henry's law constants for oxygen and nitrogen are 3.30 x 107 mm and 6.51 x 107mm respectively, calculate the composition of these gases in water.
Percentage of oxygen (O2) in air = 20 %
Percentage of nitrogen (N2) in air = 79%
Also, it is given that water is in equilibrium with air at a total pressure of 10 atm, that is, (10 × 760) mm Hg = 7600 mm Hg
Therefore, Partial pressure of oxygen, po2 = 20/100 *7600
=1520 mm Hg
Partial pressure of nitrogen,pN2 = 79/100 *7600
= 6004 mmHg
Now, according to Henry's law:
p = KH.x
For oxygen:
po2 = KH. xO2
⇒xO2 = po2 / KH
= 1520 / 3.30 X 107
= 4.61 10-5
For nitrogen:
pN2 = KH.xN2
⇒xN2 = pN2 / KH
= 6004 / 6.51 x 107
= 9.22 x 10-5
Hence, the mole fractions of oxygen and nitrogen in water are 4.61 ×10 - 5 and 9.22 × 10 - 5 respectively.
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2 Comment(s) on this Question
Y r v not considering volume, when they have given proportions by volume??
The subscript 2 must be written nicely to make it more convineint.
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