A mixture of dihydrogen and dioxygen at one bar pressure contains 20% by weight of dihydrogen. Calculate the partial pressure of dihydrogen.
Pressure of the gas mixture = 1 bar
Let us consider 100g of the mixture
So ,mass of hydrogen in the mixture = 20 g
& mass of oxygen in the mixture = 80 g
Using the respective molar masses, we get
nH = 20/ 2 = 10 mol
. nO = 80 / 32 = 2.5 mol
Then, pH = XH x Ptotal
= (nH / nH + nO) x P total
= (10 / 10 + 2.5 ) x 1
= 0.8 bar
Hence, the partial pressure of dihydrogen is 0.8 bar.
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I cannot understand this concept
Thanks
bro its very simple total pressure of dihydrogen =20% of 1 barr=0.2 barr and pressure of dioxygen =1-0.2=0.8
Very well explained And helped me for my test
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