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Question 2

Let f, g and h be functions from R to R. Show that

(f + g)oh = foh + goh

(f . g)oh = (foh) . (goh) 

Answer

To prove:

(f + g)oh = foh + goh

To Prove:

(f . g)oh = (foh) . (goh) 

Hence, (f . g)oh = (foh) . (goh)

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