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Question 9

The molar conductivity of 0.025 mol L-1 methanoic acid is

46.1 S cm2 mol-1.

Calculate its degree of dissociation and dissociation constant. Given λ0(H+)

= 349.6 S cm2 mol-1 and  λ0(HCOO-) = 54.6 S cm2 mol

Answer

C = 0.025 mol L - 1

Now, degree of dissociation:

Thus, dissociation constant:

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