Home NCERT Solutions NCERT Exemplar CBSE Sample Papers NCERT Books Class 12 Class 10
Question 16

Analysis shows that nickel oxide has the formula Ni0.98 O1.00. What fractions of nickel exist as Ni2+and Ni3+ions?

Answer

The formula of nickel oxide is Ni0.98 O1.00.

Therefore, the ratio of the number of Ni atoms to the number of O atoms,

Ni : O = 0.98 : 1.00 = 98 : 100

Now, total charge on 100 O2 - ions = 100 × ( - 2) = - 200

Let the number of Ni2+ions be x.

So, the number of Ni3+ions is 98 - x.

Now, total charge on Ni2+ions = x(+2) = +2x

And, total charge on Ni3+ions = (98 - x)(+3) = 294 - 3x

Since, the compound is neutral, we can write: 2x+ (294 - 3x) + ( - 200) = 0

⇒ - x+ 94 = 0 ⇒ x= 94

Therefore, number of Ni2+ions = 94

And, number of Ni3+ions = 98 - 94 = 4

Hence, fraction of nickel that exists as Ni2+ = 94/98 = 0.959

And, fraction of nickel that exists as Ni3+ = 4/98 = 0.041

Alternatively, fraction of nickel that exists as Ni3+= 1 - 0.959 = 0.041

Popular Questions of Class Chemistry

Recently Viewed Questions of Class Chemistry

5 Comment(s) on this Question

Write a Comment: