Question 3

A 44 mH inductor is connected to 220 V, 50 Hz ac supply. Determine the rms value of the current in the circuit.

Answer

Inductance of inductor, L = 44 mH = 44 × 10^{-3} H

Supply voltage, V = 220V

Frequency, ν = 50Hz

Angular frequency, \[\begin{align}\omega = 2\pi v\end{align}\]

Inductive reactance, \begin{align}X_{L}= \omega L = 2\pi vL = 2\pi\times50\times44\times10^{-3} \Omega\end{align}

Rms value of current is given as:

\begin{align}I = \frac{v}{X_{L}}\end{align}

\begin{align} = \frac{220}{2\pi\times50\times44\times 10^{-3}} =15.92A\end{align}

Hence, the rms value of current in the circuit is 15.92 A.

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">For a transistor amplifier, the voltage gain

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">The electrostatic force on a small sphere of charge 0.4 μC due to another small sphere of charge − 0.8 μC in air is 0.2 N.

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(b) What is the force on the second sphere due to the first?

- Q:-
A 600 pF capacitor is charged by a 200 V supply. It is then disconnected from the supply and is connected to another uncharged 600 pF capacitor. How much electrostatic energy is lost in the process?

Sankar
2020-01-11 11:08:07

Verry good i like you

anand
2018-05-08 16:07:44

Question no 3.10 se aage

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