Home Board Paper Solutions Text Book Solutions Articles NCERT Exemplar Solutions
Question 3

What is the shortest wavelength present in the Paschen series of spectral lines?

Answer

Rydberg’s formula is given as: hc/λ = 21.76 x 10-19 [1/(n1)2 - 1/(n2)2]

Where, h = Planck’s constant = 6.6 × 10 −34 Js

c = Speed of light = 3 × 10 8 m/s

(n 1 and n 2 are integers)

The shortest wavelength present in the Paschen series of the spectral lines is given for values n 1 = 3 and n 2 = ∞.

hc/λ = 21.76 x 10-19 [1/(3)2 - 1/(∞)2]

∴ λ = 6.6 x 10-34 x 3 x 108 x 9 / 21.76 x 10-19 = 8.189x10-7 m = 818.9 nm

Hence, the shortest wavelength present is 818.9 nm.

Popular Questions of Class 12th physics

Recently Viewed Questions of Class 12th physics

Write a Comment: