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Question 8

The radius of the innermost electron orbit of a hydrogen atom is 5.3 ×10 −11 m. What are the radii of the n = 2 and n =3 orbits?

Answer

The radius of the innermost orbit of a hydrogen atom, r1 = 5.3 × 10−11 m.

Let r2 be the radius of the orbit at n = 2. It is related to the radius of the innermost orbit as:

r2 = (n)2r1

= 4 x 5.3 x 10-11 = 2.12 x 10-10 m

For n = 3, we can write the corresponding electron radius as:

r3 = (n)2 r1

= 9 x 5.3 x 10-11 = 4.77 x 10-10 m

Hence, the radii of an electron for n = 2 and n = 3 orbits are 2.12 × 10−10 m and 4.77 × 10−10 m respectively.

 

 

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