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Question 3

A short bar magnet placed with its axis at 30º with a uniform externalmagnetic field of 0.25 T experiences a torque of magnitude equal to 4.5 x 10-2J. What is the magnitude of magnetic moment of the magnet?

Answer

Magnetic field strength, B= 0.25 T

Torque on the bar magnet, T= 4.5 ×10-2J

Angle between the bar magnet and the external magnetic field,θ= 30°

Torque is related to magnetic moment (M) as:

T= MB sin θ

Hence, the magnetic moment of the magnet is 0.36 J T-1.

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