Question 2

A farmer moves along the boundary of a square field of side 10 m in 40 s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds?


In fig. ABCD is a square field of side 10 m.


Time for one round = 40 s

Total time = 2 min 20 s

                = (2 x 60 + 20)s = 140s

Number of round completed =


If farmer starts from A, it will complete 3 rounds (A → B → C → D → A) at A. In the last 0.5 round starting from A, he will finish at C. 

Displacement of farmer 

Popular Questions of Class 9 Science

Write a Comment: