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Question 2

A train is travelling at a speed of 90 km h-1. Brakes are applied so as to produce a uniform acceleration of – 0.5 m s-2. Find how far the train will go before it is brought to rest.

Answer

Initial speed of the train, u = 90 km/h = 90 x 1000 / 60 x 60 = 25 m/s

Final speed of the train, v = 0 

Acceleration = −0.5 m s-2

Using equation of motion:

v2 = u2 + 2 as

(0)2 = (25)2 + 2 (−0.5) s

0 = 625 - s

 s = 625 m

Where, s is the distance covered by the train

The train will cover a distance of 625 m before it comes to rest.

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