# Class 12 Physics Moving Charges and Magnetism: NCERT Solutions for Question 24

This page focuses on the detailed Moving Charges and Magnetism question answers for Class 12 Physics Moving Charges and Magnetism, addressing the question: 'A uniform magnetic field of 3000 G is established along the positive z-direction. A rectangular loop of sides 10 cm and 5 cm carries a current of 12 A. What is the torque on the loop in the different cases shown in Figure? What is the force on each case? Which case corresponds to stable equilibrium? '. The solution provides a thorough breakdown of the question, highlighting key concepts and approaches to arrive at the correct answer. This easy-to-understand explanation will help students develop better problem-solving skills, reinforcing their understanding of the chapter and aiding in exam preparation.
Question 24

## A uniform magnetic field of 3000 G is established along the positive z-direction. A rectangular loop of sides 10 cm and 5 cm carries a current of 12 A. What is the torque on the loop in the different cases shown in Figure? What is the force on each case? Which case corresponds to stable equilibrium?

Answer

Magnetic field strength, B = 3000 G = 3000 × 10-4 T = 0.3 T

Length of the rectangular loop, l = 10 cm

Width of the rectangular loop, b = 5 cm

Area of the loop,

A = l × b = 10 × 5 = 50 cm2 = 50 × 10-4 m2

Current in the loop, I = 12 A

Now, taking the anti-clockwise direction of the current as positive and vise-versa:

(a) Torque,

From the given figure, it can be observed that A is normal to the y-z plane and B is directed along the z-axis.

The torque 1.8 x 10-2  is  N m along the negative y-direction. The force on the loop is zero because the angle between A and B is zero.

(b) This case is similar to case (a). Hence, the answer is the same as (a).

(c) Torque

From the given figure, it can be observed that A is normal to the x-z plane and B is directed along the z-axis.

The torque 1.8 x 10-2  is  N m along the negative x direction and the force is zero.

(d) Magnitude of torque is given as:

Torque is  1.8 x 10-2 N m at an angle of 240° with positive x direction. The force is zero.

(e) Torque

Hence, the torque is zero. The force is also zero.

(f) Torque

Hence, the torque is zero. The force is also zero.

In case (e), the direction of  and  is the same and the angle between them is zero. If displaced, they come back to an equilibrium. Hence, its equilibrium is stable.

Whereas, in case (f), the direction of  and  is opposite. The angle between them is 180°. If disturbed, it does not come back to its original position. Hence, its equilibrium is unstable.