Question 2

Check the injectivity and surjectivity of the following functions:

(i)* f* : **N → N** given by* f(x*) = x^{2}

(ii)* f* : **Z → Z** given by *f(x)* = x^{2}

(iii)* f* : **R → R** given by* f(x)* = x^{2}

(iv)* f *: **N → N** given by *f(x)* = x^{3}

(v)* f* : **Z → Z** given by *f(x)* = x^{3 }

Answer

(i) *f*: **N** → **N** is given by,

*f*(*x*) = *x*^{2}

It is seen that for *x*, *y* ∈**N**, *f*(*x*) = *f*(*y*) ⇒ *x*2 = *y*2 ⇒ *x* = *y*.

∴*f* is injective.

Now, 2 ∈ **N**. But, there does not exist any *x* in **N** such that *f*(*x*) = *x*^{2} = 2.

∴ *f* is not surjective.

Hence, function *f* is injective but not surjective.

(ii) *f*: **Z** → **Z** is given by,

*f*(*x*) = *x*^{2}

It is seen that *f*(-1) = *f*(1) = 1, but -1 ≠ 1.

∴ *f* is not injective.

Now,-2 ∈ **Z**. But, there does not exist any element *x* ∈**Z** such that *f*(*x*) = *x*^{2} = -2.

∴ *f* is not surjective.

Hence, function *f* is neither injective nor surjective.

(iii) *f*: **R** → **R** is given by,

*f*(*x*) = *x*^{2}

It is seen that *f*(-1) = *f*(1) = 1, but -1 ≠ 1.

∴ *f* is not injective.

Now,-2 ∈ **R**. But, there does not exist any element *x* ∈ **R** such that *f*(*x*) = *x*^{2} = -2.

∴ *f* is not surjective.

Hence, function *f* is neither injective nor surjective.

(iv) *f*: **N** → **N** given by,

*f*(*x*) = *x*^{3}

It is seen that for *x*, *y* ∈**N**, *f*(*x*) = *f*(*y*) ⇒ *x*^{3} = *y*^{3} ⇒ *x* = *y*.

∴*f* is injective.

Now, 2 ∈ **N**. But, there does not exist any element *x* in domain **N** such that *f*(*x*) = *x*^{3 }= 2.

∴ *f* is not surjective

Hence, function *f* is injective but not surjective.

(v) *f*: **Z** → **Z** is given by,

*f*(*x*) = *x*^{3}

It is seen that for *x*, *y* ∈ **Z**, *f*(*x*) = *f*(*y*) ⇒ *x*^{3} = *y*^{3} ⇒ *x* = *y*.

∴ *f* is injective.

Now, 2 ∈ **Z**. But, there does not exist any element *x* in domain **Z** such that *f*(*x*) = *x*^{3} = 2.

∴ *f* is not surjective.

Hence, function *f* is injective but not surjective.

- Q:- Determine whether each of the following relations are reflexive, symmetric and transitive:

(i) Relation R in the set A = {1, 2, 3,13, 14} defined as

R = {(x, y): 3x − y = 0}

(ii) Relation R in the set N of natural numbers defined as

R = {(x, y): y = x + 5 and x < 4}

(iii) Relation R in the set A = {1, 2, 3, 4, 5, 6} as

R = {(x, y): y is divisible by x}

(iv) Relation R in the set Z of all integers defined as

R = {(x, y): x − y is as integer}

(v) Relation R in the set A of human beings in a town at a particular time given by

(a) R = {(x, y): x and y work at the same place}

(b) R = {(x, y): x and y live in the same locality}

(c) R = {(x, y): x is exactly 7 cm taller than y}

(d) R = {(x, y): x is wife of y}

(e) R = {(x, y): x is father of y} - Q:- Given an example of a relation. Which is

(i) Symmetric but neither reflexive nor transitive.

(ii) Transitive but neither reflexive nor symmetric.

(iii) Reflexive and symmetric but not transitive.

(iv) Reflexive and transitive but not symmetric.

(v) Symmetric and transitive but not reflexive. - Q:- Show that each of the relation R in the set A = { x ∈Z: 0≤x≤12}, A={x} given by

(i) R = { (a,b) : |a - b| is a multiple of 4}

(ii) R = {(a,b):a = b} is an equivalence relation.

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- Q:- Show that each of the relation R in the set A = { x ∈Z: 0≤x≤12}, A={x} given by

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- Q:-
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*f*: R → R, given by f(x) = |x|, is neither oneone nor onto, where | x | is x, if x is positive or 0 and |x| is – x, if x is negative. - Q:-
An edge of a variable cube is increasing at the rate of 3 cm/s. How fast is the volume of the cube increasing when the edge is 10 cm long?

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- Q:- Show that the relation R in the set {1, 2, 3} given by R = {(1, 2), (2, 1)} is symmetric but neither reflexive nor transitive.
- Q:-
Show that

*f*: [–1, 1] → R, given by is one-one. Find the inverse of the function*f*: [–1, 1] → Range*f*.**(Hint: For***y*∈ Range*f*,*y*=, for some*x*in [ - 1, 1], i.e.,) - Q:- Show that the relation R in the set R of real numbers, defined as R = {(a, b): a ≤ b
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- NCERT Chapter

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