Question 20

\begin{align} \int \left(\frac {2-3sin x}{cos^2 x}\right) . dx\end{align}

Answer

\begin{align} \int \left(\frac {2-3sin x}{cos^2 x}\right) . dx\end{align}

\begin{align} =\int \left(\frac {2}{cos^2 x} - \frac{3sinx}{cos^2x}\right) . dx\end{align}

\begin{align} =2\int sec^2 x .dx   - 3 \int tan x . sec x. dx\end{align}

\begin{align} =2 tan x - 3 sec x + C\end{align} 

Popular Questions of Class 12 Mathematics

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